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nums=[5,12,7,9,21,7,14]
nums.remove(7)
print("删除第一个7后的列表：",nums)
sub_list=nums [1:4]
print("第2-4个元素组成的列表：",sub_list)

Success #stdin #stdout 0.09s 14140KB

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Standard input is empty

stdout

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删除第一个7后的列表： [5, 12, 9, 21, 7, 14]
第2-4个元素组成的列表： [12, 9, 21]

https://ideone.com/y6B9ct

language:

Python 3 (python 3.12)

created:

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public

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