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  1. nums = [5, 12, 7, 9, 21, 7, 14]
  2. count_seven = nums. count(7)  
  3. print("数字7出现的次数：",   count_seven  )
  4. if 99 not in nums:
  5.     nums. append(99)   
  6. print("添加99后的列表：",   nums    )
  7. nums.   remove   (7)   # 只删除第一个7
  8. print("删除第一个7后的列表：", nums)
  9. sub_list = nums [1:4]  
  10. print("第2~4个元素组成的列表：",    sub_list    )
Success #stdin #stdout 0.07s 14136KB
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数字7出现的次数： 2
添加99后的列表： [5, 12, 7, 9, 21, 7, 14, 99]
删除第一个7后的列表： [5, 12, 9, 21, 7, 14, 99]
第2~4个元素组成的列表： [12, 9, 21]
https://ideone.com/tPS2V4
language:
Python 3 (python  3.12)
created:
16 hours ago
visibility:
public

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