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  1. #include <stdio.h>
  2. #include <math.h>
  3.  
  4. int main() {
  5.     double pi = 0.0, term;
  6.     int n = 0;
  7.     do {
  8.         term = pow(-1, n) / (2 * n + 1);
  9.         pi += term;
  10.         n++;
  11.     } while (fabs(term) >= 1e-6);
  12.     pi *= 4;
  13.     printf("π 的近似值为：%.8f\n", pi);
  14.     return 0;
  15. }
Success #stdin #stdout 0.02s 5320KB
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Standard input is empty
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π 的近似值为：3.14159465
https://ideone.com/pUtizy
language:
C (gcc 8.3)
created:
14 days ago
visibility:
public

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