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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int i,ichi,ju,hyaku,sen,count=0;
  5. 	for(i=0;i<10000;i++){
  6. 	ichi = i % 10;              
  7.     ju = (i / 10) % 10;         
  8.     hyaku = (i / 100) % 10;     
  9.     sen = (i / 1000) % 10;   
  10.     if ((ichi + ju + hyaku + sen) % 7 == 3)
  11. 		    count++;}
  12. 		    printf("%d\n", count);
  13.  
  14. 	return 0;
  15. }
  16.  
Success #stdin #stdout 0.01s 5284KB
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stdin
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9999
stdout
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1433
https://ideone.com/g7DKJC
language:
C (gcc 8.3)
created:
16 days ago
visibility:
public

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