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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]) {
  4.     int i,j;
  5.     for (i = 0;s[i] != '\0';i++) {
  6.         ;
  7.     }
  8.     for (j = 0;s[j] == s[i - j - 1];j++) {
  9.         if (s[i / 2 / 1] == s[i - j - 1]) return 1;
  10.     }
  11.     return 0;
  12. }
  13.  
  14.  
  15. int main() {
  16.     char s[100];
  17.     scanf("%s", s);
  18.     printf("%s -> %d\n", s, isPalindrome(s));
  19.     return 0;
  20. }
  21.  
Success #stdin #stdout 0.01s 5292KB
comments (?)
stdin 
girgarig
stdout 
girgarig -> 0
https://ideone.com/fhUeUH
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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