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  1. #include <stdio.h>
  2. #define N 100
  3.  
  4. int main(void){
  5.     double t[N], v[N];
  6.     int i=0;
  7.  
  8.     while(scanf("%lf,%lf",&t[i],&v[i])==2&&i<N)
  9.         i++;
  10.  
  11.     printf("No.\t時間[s]\t電位[V]\n");
  12.  
  13.     int n=1;
  14.     for(int j=1;j<i-1;j++){
  15.         if(v[j]>v[j-1]&&v[j]>v[j+1])
  16.             printf("%d\t%.6f\t%.6f\n",n++,t[j],v[j]);
  17.     }
  18.  
  19.     return 0;
  20. }
  21.  
Success #stdin #stdout 0.01s 5324KB
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stdin
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0.000000,2.510284
0.010000,2.897269
0.020000,2.907453
0.030000,2.938005
0.040000,2.948189
0.050000,2.978740
stdout
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No.	時間[s]	電位[V]
https://ideone.com/agunrY
language:
C (gcc 8.3)
created:
12 hours ago
visibility:
public

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