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  1. nums = [5, 12, 7, 9, 21, 7, 14]
  2. count_seven = nums.count(7)
  3. print("数字7出现的次数：",count_seven)
  4. if 99 not in nums:
  5. 	nums.append(99)
  6. print("添加99后的列表：",nums)
  7.  
  8.  
  9. nums.remove(7)
  10. print("删除第一个7后的列表：", nums)
  11. sub_list = nums[1:4]
  12. print("第2~4个元素组成的列表：",sub_list)
Success #stdin #stdout 0.07s 14120KB
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数字7出现的次数： 2
添加99后的列表： [5, 12, 7, 9, 21, 7, 14, 99]
删除第一个7后的列表： [5, 12, 9, 21, 7, 14, 99]
第2~4个元素组成的列表： [12, 9, 21]
https://ideone.com/VqC7Vl
language:
Python 3 (python  3.12)
created:
17 hours ago
visibility:
public

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