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  1. #include <stdio.h>
  2. int main()
  3. {int i=1, sum=0;
  4. while(i<=100)
  5. {if (i % 3 != 0 && i % 5 != 0 && i % 10 >= 4)
  6. {sum = sum + i;}
  7. i = i + 1;}
  8. printf("条件に合う数字の和は %d です\n", sum);
  9. return 0;
  10. }
Success #stdin #stdout 0s 5320KB
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Standard input is empty
stdout
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条件に合う数字の和は 1693 です
https://ideone.com/UBQ1Zg
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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