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  1. #include <stdio.h>
  2. void fibo(int k){
  3. 	int m=1,n,l=1,p;
  4. 	if(k==0){return 1;}
  5. 	if(k==1){return 1;}
  6. 	else {for(n=2;n<k+1;n++){
  7. 		p=m;
  8. 		m=m+l;
  9. 		l=p;
  10. 	}
  11. 	printf("%d",m);
  12. 	}
  13. } 
  14.  
  15. int fibo1(int k){
  16. 	int m;
  17. 	if(k==0){return 1;}
  18. 	if(k==1){return 1;}
  19. 	else{
  20. 		m=fibo1(k-1)+fibo1(k-2);
  21. 		return m;
  22. 	}
  23. }
  24.  
  25. int main(void) {
  26. 	int l;
  27. 	fibo(7);
  28. 	l=fibo1(7);
  29. 	printf("\n%d",l);
  30. 	//fibo1 が再帰 fiboがfor文
  31. 	return 0;}
Success #stdin #stdout 0.01s 5320KB
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https://ideone.com/PSYxvI
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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