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  1. #include <stdio.h>
  2.  
  3. void ast(int n){
  4. int k;
  5. 	if(n<2){printf("0回");}
  6. 	if(n>=2){for(k=0;n>1;k++){
  7. 		n=n/2;
  8. 	}printf("%d回",k);}
  9. }
  10.  
  11. int aste(double n){
  12. 	int k;
  13. 	if(n<1){return 1;}
  14. 	else {n=n/2;
  15. 	k=aste(n)+1;
  16. 	return k;}
  17. }
  18.  
  19. int main(void) {
  20. int g;
  21. ast(8);
  22. g=aste(8)-2;
  23. printf("\n%d回",g);
  24. 	return 0;
  25. }
Success #stdin #stdout 0s 5308KB
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3回
3回
https://ideone.com/4rBC9r
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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