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  1. def ile_kolorowych(n, kolor):
  2. 	if kolor=="b":
  3. 		return n*n//2
  4. 	else:
  5. 		return (n*n-1)//2+1
  6. print(ile_kolorowych(8,"b"))
  7. print(ile_kolorowych(7,"b"))
  8. print(ile_kolorowych(8,"c"))
  9. print(ile_kolorowych(7,"c"))
  10.  
Success #stdin #stdout 0.11s 14168KB
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https://ideone.com/2yVNPn
language:
Python 3 (python  3.12)
created:
14 days ago
visibility:
public

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